Welcome toVigges Developer Community-Open, Learning,Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.3k views
in Technique[技术] by (71.8m points)

swift - Constant unassigned optional will not be nil by default

My understanding so far : If you define an optional variable without assign any values, the compiler will automatically assign the nil

Code Snippets:

A :

var someOptional : Int? //Change to `let` to trigger error 
var aDefaultValue = 42
var theAnswer = someOptional ?? aDefaultValue

The code snippet above works fine, however, when I changed the variable someOptional to a constant, the compiler yelled an error (Please see the attached figure below)

enter image description here

B :

I then tried the similar codes to down to the problem.

var someOptional : Int?
print(someOptional)

Still, it works fine with variable while failed with the constant type.

enter image description here

Conclusion:

If you define a constant optional you have to assign the nil explicitly if you mean that. Because it looks useless (why do you need a constant option with assigned with nil), if the compiler did that for you automatically it may introduce an error.

Question:

Why does the compiler assume nil for var declared optionals but not for let declared optionals?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Yes it's correct

An optional variable doesn't need to be manually initialized. If you read it before having populated it does contain nil.

From Apple docs

If you define an optional variable without providing a default value, the variable is automatically set to nil for you [...]

On the other hand the compiler does force you to manually initialize an Optional constant (let) before you can read it.

Unlike a variable, the value of a constant cannot be changed once it is set. Attempting to do so is reported as an error when your code is compiled [...]

Why?

A constant can be written only once. It doesn't need to happened on the same line it is initialized but it must happened before your read it.

E.g. this code works fine

let num: Int?
num = 1
print(num)

However if the compiler had put a temporary nil value inside num then the constant would have been wrote twice. Which is against the concept of constant.

let num: Int?
print(num) // nil ??? <- this can't work! 
num = 1
print(num) // 1

Another example

This code snippet works fine

func printArea(width: Int?, height:Int?) {
    let area: Int?
    if let width = width, height = height {
        area = width * height
    } else {
        area = nil
    }
    print(area)
}

Again, if the compiler had put a temporary nil value inside area then...

func printArea(width: Int?, height:Int?) {
    let area: Int?
    print(area) // not possible! area is going to change in a moment
     if let width = width, height = height {
        area = width * height
    } else {
        area = nil
    }
    print(area)
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to Vigges Developer Community for programmer and developer-Open, Learning and Share

2.1m questions

2.1m answers

63 comments

56.5k users

...