scala - Test if implicit conversion is available

Question

I am trying to detect if an implicit conversion exists, and depending on it, to execute some code. For instance :

if (x can-be-converted-to SomeType)
  return something(conversion(x))
else
  return someotherthing(x)

For instance, x is an Int and should be converted to a RichInt. Is this possible in Scala? If yes, how?

Thanks

Answer 1

As others already mentioned implicits are resolved at compile time so maybe you should rather use type classes to solve problems like this. That way you have the advantage that you can extend functionality to other types later on.

Also you can just require an existing implicit value but have no way of directly expressing non-existence of an implicit value except for the default arguments.

Jean-Phiippe's solution using a default argument is already quite good but the null could be eliminated if you define a singleton that can be put in place of the implicit parameter. Make it private because it is actually of no use in other code and can even be dangerous as implicit conversions can happen implicitly.

private case object NoConversion extends (Any => Nothing) {
   def apply(x: Any) = sys.error("No conversion")
}

// Just for convenience so NoConversion does not escape the scope.
private def noConversion: Any => Nothing = NoConversion

// and now some convenience methods that can be safely exposed:

def canConvert[A,B]()(implicit f: A => B = noConversion) =
  (f ne NoConversion)

def tryConvert[A,B](a: A)(implicit f: A => B = noConversion): Either[A,B] = 
  if (f eq NoConversion) Left(a) else Right(f(a))

def optConvert[A,B](a: A)(implicit f: A => B = noConversion): Option[B] =
  if (f ne NoConversion) Some(f(a)) else None